Monty Hall

Aug. 17th, 2011 04:15 pm
andrewducker: (Default)
[personal profile] andrewducker
[Poll #1770413]

Explanation

I have known what the answer was for ages, but for some reason it only "clicked" in my head today. You can blame [livejournal.com profile] sarahs_muse for triggering it.

Date: 2011-08-17 06:06 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Interestingly, this is a situation where getting it wrong and winning a goat is actually slightly beneficial!

And you do, because you haven't proven you're not in universe #2. After all, the first one she checked could have been either one.

Date: 2011-08-17 06:08 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
More particularly: There's no way to tell if the first one she checked was in either position. So all you know is that they're not both male.

Date: 2011-08-17 06:22 pm (UTC)
From: [identity profile] chuma.livejournal.com
It's irrelevent. If you are given a fact that one is female, and assuming there are no hidden facts like eggs from the same litter have to be the same gender, then it is a 50-50 that the other one is female.

Date: 2011-08-17 06:26 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Nope! The trick is that you're not determining the sex of a random baby, you're determining the sex of a random baby from a set of two random babies.

The possible sets of two random babies are:

MM
MF
FM
FF

All of those two-baby sets are equally likely.
You know that one of the two babies is female, but not which one of the two - your Head Scientist's slightly misleading "first one" is "the first one she checked" and, if the original comment could be edited, it would be by now.

But!

All you know is that you have four equally-likely possibilities... and you're DEFINITELY not in possibliity #1, "MM".

This leaves you with three possible combinations:

MF
FM
FF
where are least one baby is female.

And in 2/3 of the cases, the second baby is male.

(This is a classic nonintuitive result, like Monty Hall's problem.)

Date: 2011-08-17 06:29 pm (UTC)
From: [identity profile] chuma.livejournal.com
Wrong.

You are not weighting your chances. Your options are MF FM or FF but the chance of having a male are 50-50. You then have a 50% chance of the Male being in place 1 or 2. Thus you have 25% chance of MF and FM and a 50% chance of FF.

Date: 2011-08-17 06:32 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Intriguing argument.

Imagine that Monty Hall has three goats and a car, behind four doors. The car is equally likely to be behind each door, such that your odds are:

1: 25%
2: 25%
3: 25%
4: 25%

Monty opens door #1 to reveal no car.

*I* say that your odds are now
1: 0%
2: 33%
3: 33%
4: 33%

*You* say that your odds are now:
1: 0%
2: 25%
3: 25%
4: 50%

I am wondering why you think this is.

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Date: 2011-08-17 06:26 pm (UTC)
From: [identity profile] chuma.livejournal.com
Although if you wish to apply the above to the solution, you need to add % chances :-

Before you know one is female the options are:
MM 25%
MF 25%
FM 25%
FF 25%

AFTER you know one is female the options are:
MM 0%
MF 25%
FM 25%
FF 50%

Date: 2011-08-17 06:29 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Why does the lack of MM make the MF possibilities less likely?

Date: 2011-08-17 06:35 pm (UTC)
From: [identity profile] chuma.livejournal.com
It doesn't. There is a 50% chance of FF or MF/FM. The location of Male or Female doesn't change the fact that each option is 50% as a whole. There is a 50-50 that the Male is in the 1st or 2nd slot so that is half of the 50% (25%) for each option.

Your method is not a Monty Hall problem. That is when you are given NEW information AFTER a decision has been made. This example gives informations BEFORE a decision has been made.

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Date: 2011-08-17 06:30 pm (UTC)
From: [identity profile] bracknellexile.livejournal.com
Without a position, i.e. the, "I've checked one and it's female" as discussed elsewhere, surely that's:

MM 0%
MF 33%
FM 33%
FF 33%

Date: 2011-08-17 06:45 pm (UTC)
From: [identity profile] chuma.livejournal.com
Okay if we are going to stick to this modal, Lets assume it is a FF scenario. How do you know the first female she saw is the one in the 1st slot and not in the 2nd? If you want to keep this option then the true options are:

M F*
F* M
F* F
F F*

Where the F* is the one that we know about. Now given them all 25% and you have a true modal.

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Date: 2011-08-17 09:48 pm (UTC)
From: [identity profile] atreic.livejournal.com
In the interest of supporting people who appear to be right on the internet, I've read the wikipedia page and thought about it, and you appear to be right.

The crux is clearly

From all families with two children, at least one of whom is a boy, a family is chosen at random. This would yield the answer of 1/3.

From all families with two children, one child is selected at random, and the sex of that child is specified. This would yield an answer of 1/2.

You (or nature, or hot velociraptor sex, or the scientist breeding velociraptors, or people who don't understand stats on the internet) have selected a family of two velociraptors at random from the set of all possible families of two velociraptors, and have then acquired the additional information that one velociraptor is a girl. It's clearly the second scenario, not the first. Unless the scientist was producing embryos in some strange probability space where they had to have at least one girl embryo. But if they'd done that they wouldn't need to check them, because they'd know they had at least one girl ;-)

Date: 2011-08-17 10:06 pm (UTC)
From: [identity profile] chuma.livejournal.com
Bless you :)

I knew someone would put it more succinctly than me. :D

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Date: 2011-08-18 09:11 am (UTC)
From: [identity profile] ptc24.livejournal.com
My reading of "the first one" means the options are:

MM 0%
MF 0%
FM 50%
FF 50%

Date: 2011-08-17 06:23 pm (UTC)
From: [identity profile] bracknellexile.livejournal.com
Doesn't "the first" imply a position?

If she'd said, "I've checked one, and it's female," rather than "I've checked the first one, and it's female," then I'd agree with you. I can see your point, but the implied position in the quote means I'm with Andy on this one... for now :)

Date: 2011-08-17 06:27 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
You're right, it's a bad phrasing. "the first one" was meant to mean "I have checked one, and will soon check the other".

Either way, there's no position.

Date: 2011-08-17 06:32 pm (UTC)
From: [identity profile] bracknellexile.livejournal.com
Yeah, I saw your reply to Andy below. With the revised phrasing and no position, I agree that it's a 2/3 chance the other is male.

Date: 2011-08-17 06:22 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
She's checked one of them.

In the set of all two-raptor pairs, you don't actually know which one she's checked.

My wording "the first one" really should have been the more clear "I have checked one". The traditional Science Announcement is "Yes, at least one is female".

All you know is that they're not both male.

Date: 2011-08-17 06:35 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
Only if you accept "I've checked one and it's female" to mean "I have numbered them, and determined that #1 is female, thus eliminating TWO of the possible results", instead of the intended (and sloppily worded) "I have determined that one of them is female, without caring which"

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Date: 2011-08-18 10:13 am (UTC)
From: [identity profile] atreic.livejournal.com
I understand this now! You're wrong, because 'I have checked one and it is female' is not the same as 'at least one is female'. Some cases of the latter will not be picked up by the test.

Ie, if the raptor family is a boy and a girl, it would always be included in 'at least one is female'. But half the time it would not be included in 'I checked 1 and it was female' as you might have checked the boy.

Or as a friend of mine said so much better than I could '"First-born" and "first one I looked at" are equivalent as far as probabilities are concerned, and the probability is 1/2.

If instead I took a sample of both velociraptor's DNA, mixed them together and said "Hey I've found some Y chromosomes, at least one velociraptor is male" THEN the probability that both are male is 1/3.'

Date: 2011-08-18 01:50 pm (UTC)
From: [identity profile] lizw.livejournal.com
If instead I took a sample of both velociraptor's DNA, mixed them together and said "Hey I've found some Y chromosomes, at least one velociraptor is male" THEN the probability that both are male is 1/3.'

This is brilliant.

Date: 2011-08-18 04:36 pm (UTC)
From: [identity profile] damerell.livejournal.com
"I have checked one and it is female" obviously is not the same as "at least one is female". The latter statement may imply having checked both.

Date: 2011-08-18 05:01 pm (UTC)
From: [identity profile] theweaselking.livejournal.com
The intended interpretation was that the owner of the park wouldn't know which was which - similar to "One is female, the other is OH GOD IT HAS MY NECK ARGH WHY DID WE BREED RAPTORS WHYYYYYYY"

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