Monty Hall
Aug. 17th, 2011 04:15 pm![[personal profile]](https://www.dreamwidth.org/img/silk/identity/user.png)
[Poll #1770413]
Explanation
I have known what the answer was for ages, but for some reason it only "clicked" in my head today. You can blame
sarahs_muse for triggering it.
Explanation
I have known what the answer was for ages, but for some reason it only "clicked" in my head today. You can blame
![[livejournal.com profile]](https://www.dreamwidth.org/img/external/lj-userinfo.gif)
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Date: 2011-08-17 06:06 pm (UTC)And you do, because you haven't proven you're not in universe #2. After all, the first one she checked could have been either one.
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Date: 2011-08-17 06:08 pm (UTC)no subject
Date: 2011-08-17 06:22 pm (UTC)no subject
Date: 2011-08-17 06:26 pm (UTC)The possible sets of two random babies are:
MM
MF
FM
FF
All of those two-baby sets are equally likely.
You know that one of the two babies is female, but not which one of the two - your Head Scientist's slightly misleading "first one" is "the first one she checked" and, if the original comment could be edited, it would be by now.
But!
All you know is that you have four equally-likely possibilities... and you're DEFINITELY not in possibliity #1, "MM".
This leaves you with three possible combinations:
MF
FM
FF
where are least one baby is female.
And in 2/3 of the cases, the second baby is male.
(This is a classic nonintuitive result, like Monty Hall's problem.)
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Date: 2011-08-17 06:29 pm (UTC)You are not weighting your chances. Your options are MF FM or FF but the chance of having a male are 50-50. You then have a 50% chance of the Male being in place 1 or 2. Thus you have 25% chance of MF and FM and a 50% chance of FF.
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Date: 2011-08-17 06:32 pm (UTC)Imagine that Monty Hall has three goats and a car, behind four doors. The car is equally likely to be behind each door, such that your odds are:
1: 25%
2: 25%
3: 25%
4: 25%
Monty opens door #1 to reveal no car.
*I* say that your odds are now
1: 0%
2: 33%
3: 33%
4: 33%
*You* say that your odds are now:
1: 0%
2: 25%
3: 25%
4: 50%
I am wondering why you think this is.
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Date: 2011-08-17 06:26 pm (UTC)Before you know one is female the options are:
MM 25%
MF 25%
FM 25%
FF 25%
AFTER you know one is female the options are:
MM 0%
MF 25%
FM 25%
FF 50%
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Date: 2011-08-17 06:29 pm (UTC)no subject
Date: 2011-08-17 06:35 pm (UTC)Your method is not a Monty Hall problem. That is when you are given NEW information AFTER a decision has been made. This example gives informations BEFORE a decision has been made.
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Date: 2011-08-17 06:30 pm (UTC)MM 0%
MF 33%
FM 33%
FF 33%
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Date: 2011-08-17 06:45 pm (UTC)M F*
F* M
F* F
F F*
Where the F* is the one that we know about. Now given them all 25% and you have a true modal.
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Date: 2011-08-17 09:48 pm (UTC)The crux is clearly
From all families with two children, at least one of whom is a boy, a family is chosen at random. This would yield the answer of 1/3.
From all families with two children, one child is selected at random, and the sex of that child is specified. This would yield an answer of 1/2.
You (or nature, or hot velociraptor sex, or the scientist breeding velociraptors, or people who don't understand stats on the internet) have selected a family of two velociraptors at random from the set of all possible families of two velociraptors, and have then acquired the additional information that one velociraptor is a girl. It's clearly the second scenario, not the first. Unless the scientist was producing embryos in some strange probability space where they had to have at least one girl embryo. But if they'd done that they wouldn't need to check them, because they'd know they had at least one girl ;-)
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Date: 2011-08-17 10:06 pm (UTC)I knew someone would put it more succinctly than me. :D
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Date: 2011-08-18 09:11 am (UTC)MM 0%
MF 0%
FM 50%
FF 50%
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Date: 2011-08-17 06:23 pm (UTC)If she'd said, "I've checked one, and it's female," rather than "I've checked the first one, and it's female," then I'd agree with you. I can see your point, but the implied position in the quote means I'm with Andy on this one... for now :)
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Date: 2011-08-17 06:27 pm (UTC)Either way, there's no position.
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Date: 2011-08-17 06:32 pm (UTC)no subject
Date: 2011-08-17 06:11 pm (UTC)no subject
Date: 2011-08-17 06:22 pm (UTC)In the set of all two-raptor pairs, you don't actually know which one she's checked.
My wording "the first one" really should have been the more clear "I have checked one". The traditional Science Announcement is "Yes, at least one is female".
All you know is that they're not both male.
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Date: 2011-08-17 06:25 pm (UTC)I know either that I'm in universes 1/3 or in universe 3/4. In either case I have a 50% chance of the other one being male and the other one being female.
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Date: 2011-08-17 06:35 pm (UTC)(no subject)
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Date: 2011-08-18 10:13 am (UTC)Ie, if the raptor family is a boy and a girl, it would always be included in 'at least one is female'. But half the time it would not be included in 'I checked 1 and it was female' as you might have checked the boy.
Or as a friend of mine said so much better than I could '"First-born" and "first one I looked at" are equivalent as far as probabilities are concerned, and the probability is 1/2.
If instead I took a sample of both velociraptor's DNA, mixed them together and said "Hey I've found some Y chromosomes, at least one velociraptor is male" THEN the probability that both are male is 1/3.'
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Date: 2011-08-18 01:50 pm (UTC)This is brilliant.
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Date: 2011-08-18 04:36 pm (UTC)no subject
Date: 2011-08-18 05:01 pm (UTC)(no subject)
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